Tìm số phức z thỏa $(z+1)^4+2(z+1)^2+(z+4)^2+1=0$
dangj khó đó –  gaara.sshn 26-11-12 09:51 PM
dangj 1 điểm –  luffykunneu 26-11-12 09:41 PM
dạng toán gỡ điểm –  babylionneu 26-11-12 09:01 PM
Ta có:
     $(z+1)^4+2(z+1)^2+(z+4)^2+1=0$
$\Leftrightarrow z^4+4z^3+9z^2+16z+20=0$
$\Leftrightarrow (z^2+4)(z^2+4z+5)=0$
$\Leftrightarrow \left[ \begin{array}{l} z=\pm2i\\ z=-2\pm i \end{array} \right.$
like đáp án –  phong8 27-11-12 08:27 AM
thanks nha –  gaara.sshn 26-11-12 09:51 PM
hyahyahya –  luffykunneu 26-11-12 09:41 PM
cách giải ngắn nhỉ –  babylionneu 26-11-12 09:02 PM

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