Cho đường tròn tâm $O$, bán kính  $R=20cm$. Gọi  $M$  là điểm ở ngoài đường tròn với  $OM=30cm$. Vẽ tiếp tuyến  $MT$ và cát tuyến  $MAB$ với đường tròn. Biết $AB=5cm$
a) Tính  $MT$.
b) Tính  $MA,  MB$.
c)  Đường tròn ngoại tiếp  $\Delta AOB$  cắt  $MO$ tại  $E$. Tính  $OE$.

 a) Ta có:  $MT^2=MO^2-R^2=900-400=500    \Rightarrow    MT=10 \sqrt{5}  $ cm

b) Đặt  $MA=x (x>0)    \Rightarrow    MB=x+5$
Ta có:  $MA.MB=MT^2$
$\Leftrightarrow     x(x+5)=500$
$\Leftrightarrow     x^2+5x-500=0$
$\Leftrightarrow     x_1=20; x_2=-25 $  (loại)
Vậy  $MA=20cm;     MB=20+5=25 cm.$

c) Ta có: $ME.MO=MA.MB=MT^2=500$
$\Leftrightarrow     ME=\frac{500}{MO}=\frac{500}{30}=\frac{50}{3}     \Rightarrow     ME=\frac{50}{3} cm $
Vậy  $OE=MO-ME=30-\frac{50}{3}=\frac{40}{3}      \Rightarrow     OE=\frac{40}{3} cm.$

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