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	3	thêm 26 ký tự trong đáp án		Sửa 14-11-16 07:10 AM ❄⊰๖ۣۜNgốc๖ۣۜ ⊱ ❄ 1
Ta có: $BE=BD+DE$ và $CD=CE+ED$$\Rightarrow BE=CD(do BD=CE)$$\Rightarrow \triangle ABE=\triangle ACD$$\Rightarrow AE=AD$$\Rightarrow \triangle ABD=\triangle ACE(AB=AC;BD=CE;AD=AE)$Vậy ....... BE=BD+DECD=CE+ED$\Rightarrow BE=CD(do BD=CE)$$\Rightarrow \triangle ABE=\triangle ACD$$\Rightarrow AE=AD$$\Rightarrow \triangle ABD=\triangle ACE(AB=AC;BD=CE;AD=AE)$ Ta có: $BE=BD+DE$ và $CD=CE+ED$$\Rightarrow BE=CD(do BD=CE)$$\Rightarrow \triangle ABE=\triangle ACD$$\Rightarrow AE=AD$$\Rightarrow \triangle ABD=\triangle ACE(AB=AC;BD=CE;AD=AE)$Vậy .......

	2	thêm 8 ký tự trong đáp án		Sửa 14-11-16 07:08 AM ❄⊰๖ۣۜNgốc๖ۣۜ ⊱ ❄ 1
BE=BD+DECD=CE+ED$\Rightarrow BE=CD(do BD=CE)$$\Rightarrow \triangle ABE=\triangle ACD$$\Rightarrow AE=AD$$\Rightarrow \triangle ABD=\triangle ACE(AB=AC;BD=CE;AD=AE)$ BE=BD+DECD=CE+ED\Rightarrow BE=CD(do BD=CE)\Rightarrow \triangle ABE=\triangle ACD\Rightarrow AE=AD\Rightarrow \triangle ABD=\triangle ACE(AB=AC;BD=CE;AD=AE) BE=BD+DECD=CE+ED$\Rightarrow BE=CD(do BD=CE)$$\Rightarrow \triangle ABE=\triangle ACD$$\Rightarrow AE=AD$$\Rightarrow \triangle ABD=\triangle ACE(AB=AC;BD=CE;AD=AE)$

	1	tạo mới
BE=BD+DECD=CE+ED\Rightarrow BE=CD(do BD=CE)\Rightarrow \triangle ABE=\triangle ACD\Rightarrow AE=AD\Rightarrow \triangle ABD=\triangle ACE(AB=AC;BD=CE;AD=AE)

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