A=\frac{(x^2+10x+16)(x^2+10x+24)+2008}{x^2+10x+21}đặt$: x^2+10x+16=a\Rightarrow A=\frac{a^2+8a+2008}{a+5}=\frac{(a+5)(a+3)+1993}{t+5}vậy dư là 1993$
A=\frac{(x^2+10x+16)(x^2+10x+24)+2008}{x^2+10x+21}đặt$: x^2+10x+16=a\Rightarrow A=\frac{a^2+8a+2008}{a+5}=\frac{(a+5)(a+3)+1993}{
a+5}
vậy dư là 1993$