Quay lại đáp án

	2	thêm 1 ký tự trong đáp án
Phân tích ra được:$y=7x-x^2+21-3x=21+4x-x^2=25-(x^2-4x+4)=25-(x-)^2\leq -0=. $Dấu$ = $xảy ra$ \Leftrightarrow x= $. Thỏa mãn$ -3\leq x\leq7$. Phân tích ra được:$y=7x-x^2+21-x=21+6x-x^2=30-(x^2-6x+9)=30-(x-)^2\leq -0=. $Dấu$ = $xảy ra$ \Leftrightarrow x= $. Thỏa mãn$ -3\leq x\leq7$. Phân tích ra được:$y=7x-x^2+21-3x=21+4x-x^2=25-(x^2-4x+4)=25-(x-)^2\leq -0=. $Dấu$ = $xảy ra$ \Leftrightarrow x= $. Thỏa mãn$ -3\leq x\leq7$.

	1	tạo mới
Phân tích ra được: $y=7x-x^2+21-x=21+6x-x^2=30-(x^2-6x+9)=30-(x-3)^2\leq 30-0=30.$ Dấu $=$ xảy ra $\Leftrightarrow x=3$ . Thỏa mãn $-3\leq x\leq7$ .

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