Quay lại đáp án

	2	sửa đáp án		Sửa 29-02-16 04:00 PM tran85295 21 2
Gọi $x =\tan A,y= \tan B, z = \tan C$ Ta có $\tan A. \tan B. \tan C=\tan A+ \tan B+ \tan C$ $\Leftrightarrow \tan A(\tan B. \tan C-1)= \tan B + \tan C$ $\Leftrightarrow \frac{\tan B+ \tan C}{1-\tan B. \tan C}=-tan A$ $\Leftrightarrow \tan (B)=\tan (\pi -) $\Leftrightarrow A+B+C= \pi$ \Leftrightarrow T = \cot A+ \cot B + \cot C \ge \sqrt 3 $ Gọi $x =\tan A,y= \tan B, z = \tan C$ Ta có $\tan A. \tan B. \tan C=\tan A+ \tan B+ \tan C$ $\Leftrightarrow \tan A(\tan B. \tan C-1)= \tan B + \tan C$ $\Leftrightarrow \frac{\tan B+ \tan C}{1-\tan B. \tan C}=-tan A$ $\Leftrightarrow \tan (B)=\tan (\pi -) $\Leftrightarrow A+B+C= \pi$ \Leftrightarrow T = \cot A+ \cot B + \cot C \ge \sqrt 3 $ Gọi $x =\tan A,y= \tan B, z = \tan C$ Ta có $\tan A. \tan B. \tan C=\tan A+ \tan B+ \tan C$ $\Leftrightarrow \tan A(\tan B. \tan C-1)= \tan B + \tan C$ $\Leftrightarrow \frac{\tan B+ \tan C}{1-\tan B. \tan C}=-tan A$ $\Leftrightarrow \tan (B)=\tan (\pi -) $\Leftrightarrow A+B+C= \pi$ \Leftrightarrow T = \cot A+ \cot B + \cot C \ge \sqrt 3 $

	1	tạo mới		Trả lời 29-02-16 03:58 PM tran85295 21 2
Gọi $x =\tan A,y= \tan B, z = \tan C$ Ta có $\tan A. \tan B. \tan C=\tan A+ \tan B+ \tan C$ $\Leftrightarrow \tan A(\tan B. \tan C-1)= \tan B + \tan C$ $\Leftrightarrow \frac{\tan B+ \tan C}{1-\tan B. \tan C}=-tan A$ $\Leftrightarrow \tan (A+B)=\tan (\pi -C)$ $\Leftrightarrow A+B+C= \pi$ $\Leftrightarrow T = \cot A+ \cot B + \cot C \ge \sqrt 3$

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