pt⇔√(x+12)2+34-√(x−1)2+1=mĐặt →u(x+12;√32);→v(x-1;1) Ta có:||→u|−|→v||≤$\left| {\overrightarrow{u}$\overrightarrow{v}} \right|⇒\left| {m} \right|≤\sqrt{4-\sqrt{3}}⇔$−$√4−√3\leqm\leq$$\sqrt{4-\sqrt{3}}$
pt
⇔√(x+12)2+34-
√(x−1)2+1=mĐặt
→u(x+
12;
√32);
→v(x-1;1) Ta có:
||→u|−|→v||≤$\left| {\overrightarrow{u}
-\overrightarrow{v}} \right|
⇒\left| {m} \right|
≤\sqrt{4-\sqrt{3}}
⇔$−$√4−√3\leq
m\leq$$\sqrt{4-\sqrt{3}}$