M\in \Delta \Rightarrow M(2+2t;3+t)Lúc này MA=5\Leftrightarrow \sqrt{(2+2t-0}^{2}+(3+t-1)^{2}}=5\Leftrightarrow (2+2t-0}^{2}+(3+t-1)^{2}=25\Leftrightarrow 5t^{2}+12t-17=0\Leftrightarrow t=1 t=-17/5vậy M_{1}(4;4) M_{2}(-24/5;-2/5)
$M\in \Delta \Rightarrow M(2+2t;3+t)
$Lúc này MA=5
$\Leftrightarrow \sqrt{(2+2t-0}^{2}+(3+t-1)^{2}}=5
$$\Leftrightarrow (2+2t-0}^{2}+(3+t-1)^{2}=25
$\Leftrightarrow 5t^{2}+12t-17=0\Leftrightarrow t=1 t=-17/5vậy M_{1}(4;4) M_{2}(-24/5;-2/5)