phương trình mặt cầu (S):x2 + y2 + z2 – 4x + 6y – 2z
– 2 = 0 => tam I (2;-3;1) và bán kính R = 4mặt phẳng (P): 2x−y+2z+3=0Ơ => nP
= (2;-1;2)và mp (B) // mp(P) => vtcp n(B) = n(P)
= (2;-1;2) => ptmp (B): 2x - y + 2z + D = 0ta có : d[(B)/(S)] = d[I/(B)] = R => \frac{I9 + DI}{3} = 4 =>TH1: 9 + D = 12 => D = 3 => (B) : 2x - y + 2z + 3 = 0 =>TH2: - 9 - D = 12 => D = -21 => (B) : 2x - y + 2z - 21 = 0TH1) co (B) : 2x - y + 2z + 3 = 0co phuong trinh duong thag (d) qua I (2;-3;1) va ud
= n(B) = (2, -1, 2) => (d) x = 2 +2t y = -3 - t z = 1 + 2ttoa do tiep diem A la nghiep cua hpt: x = 2 +2t y = -3 - t z = 1 + 2t 2x - y + 2z + 3 = 0 => t = - 4/3 => A (-2/3; -5/3 ; -5/3)toa do tiep diem B la nghiep cua hpt: x = 2 +2t y = -3 - t z = 1 + 2t 2x - y + 2z - 21 = 0 => t = 4/3 => B (14/3; -13/3 ; 11/3)trong luc lam neu sai tinh toan mog ban thog cam-43
phương trình mặt cầu (S):x2 + y2 + z2 – 4x + 6y – 2z
– 2 = 0 => tam I (2;-3;1) và bán kính R = 4mặt phẳng (P): 2x−y+2z+3=0Ơ => nP
= (2;-1;2)và mp (B) // mp(P) => vtcp n(B) = n(P)
= (2;-1;2) => ptmp (B): 2x - y + 2z + D = 0ta có : d[(B)/(S)] = d[I/(B)] = R => \frac{I9 + DI}{3} = 4 =>TH1: 9 + D = 12 => D = 3 => (B) : 2x - y + 2z + 3 = 0 =>TH2: - 9 - D = 12 => D = -21 => (B) : 2x - y + 2z - 21 = 0TH1) co (B) : 2x - y + 2z + 3 = 0co phuong trinh duong thag (d) qua I (2;-3;1) va ud = nb = (2,-1,2) => (d) x = 2 +2t y = -3 - t z = 1 + 2ttoa do tiep diem A la nghiep cua hpt: x = 2 +2t y = -3 - t z = 1 + 2t 2x - y + 2z + 3 = 0 => t = - 4/3 => A (-2/3; -5/3 ; -5/3)toa do tiep diem B la nghiep cua hpt: x = 2 +2t y = -3 - t z = 1 + 2t 2x - y + 2z - 21 = 0 => t = 4/3 => B (14/3; -13/3 ; 11/3)trong luc lam neu sai tinh toan mog ban thog cam-43
phương trình mặt cầu (S):x2 + y2 + z2 – 4x + 6y – 2z
– 2 = 0 => tam I (2;-3;1) và bán kính R = 4mặt phẳng (P): 2x−y+2z+3=0Ơ => nP
= (2;-1;2)và mp (B) // mp(P) => vtcp n(B) = n(P)
= (2;-1;2) => ptmp (B): 2x - y + 2z + D = 0ta có : d[(B)/(S)] = d[I/(B)] = R => \frac{I9 + DI}{3} = 4 =>TH1: 9 + D = 12 => D = 3 => (B) : 2x - y + 2z + 3 = 0 =>TH2: - 9 - D = 12 => D = -21 => (B) : 2x - y + 2z - 21 = 0TH1) co (B) : 2x - y + 2z + 3 = 0co phuong trinh duong thag (d) qua I (2;-3;1) va ud
= n
(B) = (2,
-1,
2) => (d) x = 2 +2t y = -3 - t z = 1 + 2ttoa do tiep diem A la nghiep cua hpt: x = 2 +2t y = -3 - t z = 1 + 2t 2x - y + 2z + 3 = 0 => t = - 4/3 => A (-2/3; -5/3 ; -5/3)toa do tiep diem B la nghiep cua hpt: x = 2 +2t y = -3 - t z = 1 + 2t 2x - y + 2z - 21 = 0 => t = 4/3 => B (14/3; -13/3 ; 11/3)trong luc lam neu sai tinh toan mog ban thog cam
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