Gọi (C) có tâm I(a;b) bán kính RIA2=(a−1)2+(b−2)2IB2=(a−3)2+(b−4)2d(I,d)=I(3a+b−3I)/√1{IA2=IB2IA=d(I,d){a+b=510(a2+b2−2a−4b+5)=|3a+b−3|{a=5−bb=72hoặcb=1a=32;b=72⇒(C):(x−32)2+(y−72)2=√102a=4;b=1⇒(C):(x−4)2+(y−1)2=√10
Gọi
(C) có tâm
I(a;b) bán kính R
IA2=(a−1)2+(b−2)2IB2=(a−3)2+(b−4)2$d(I,d)=I(3a+b-3I)/ \sqrt{1
0}
{IA2=IB2IA=d(I,d){a+b=510(a2+b2−2a−4b+5)=|3a+b−3|{a=5−bb=72hoặcb=1a=\frac{3}{2} ; b=\frac{7}{2} \Rightarrow (C): (x-\frac{3}{2} )^2 + (y-\frac{7}{2} )^2 = \frac{\sqrt{10} }{2} $$a= 4 ; b=1 \Rightarrow (C): (x-4)^2 + (y-1)^2 = \sqrt{10} $