Quay lại đáp án

	2	thêm 109 ký tự trong đáp án
1,Ta có: $\overrightarrow{AB}(0; 1; 0), \overrightarrow{AC}(0; 0; 1); \overrightarrow{AD}(1; 1; 0)$ , suy ra: $[\overrightarrow{AB}. \overrightarrow{AC}].\overrightarrow{AD}=(1; 0; 0)(1;1;0)=1\neq 0$ $\Rightarrow \overrightarrow{AB}, \overrightarrow{AC}; \overrightarrow{AD}$ không đồng phẳng $\Leftrightarrow$ A, B, C, D không đồng phẳngTa có: $V_{ABCD}=\frac{1}{6}\|[\overrightarrow{AB}. \overrightarrow{AC}].\overrightarrow{AD}\|=\frac{1}{6}$ 1,Ta có: $\overrightarrow{AB}(0; 1; 0), \overrightarrow{AC}(0; 0; 1); \overrightarrow{AD}(1; 1; 0)$ , suy ra: $[\overrightarrow{AB}. \overrightarrow{AC}].\overrightarrow{AD}=(1; 0; 0)(1;1;0)=1\neq 0$ $\Rightarrow \overrightarrow{AB}, \overrightarrow{AC}; \overrightarrow{AD}$ không đồng phẳng $\Leftrightarrow$ A, B, C, D không đồng phẳng 1,Ta có: $\overrightarrow{AB}(0; 1; 0), \overrightarrow{AC}(0; 0; 1); \overrightarrow{AD}(1; 1; 0)$ , suy ra: $[\overrightarrow{AB}. \overrightarrow{AC}].\overrightarrow{AD}=(1; 0; 0)(1;1;0)=1\neq 0$ $\Rightarrow \overrightarrow{AB}, \overrightarrow{AC}; \overrightarrow{AD}$ không đồng phẳng $\Leftrightarrow$ A, B, C, D không đồng phẳngTa có: $V_{ABCD}=\frac{1}{6}\|[\overrightarrow{AB}. \overrightarrow{AC}].\overrightarrow{AD}\|=\frac{1}{6}$

	1	tạo mới
1,Ta có: $\overrightarrow{AB}(0; 1; 0), \overrightarrow{AC}(0; 0; 1); \overrightarrow{AD}(1; 1; 0)$ , suy ra: $[\overrightarrow{AB}. \overrightarrow{AC}].\overrightarrow{AD}=(1; 0; 0)(1;1;0)=1\neq 0$ $\Rightarrow \overrightarrow{AB}, \overrightarrow{AC}; \overrightarrow{AD}$ không đồng phẳng $\Leftrightarrow$ A, B, C, D không đồng phẳng

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