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	3	thêm 5 ký tự trong đề bài		Sửa 13-04-16 03:38 PM Hàn Thiên Dii 16 3
tim gtln gtnn Cho $x, y$ khong am thay doi thoa man $x+y=1$. Tim GTLN, GTNN cua bieu thuc $S=(4x^2+3y)(4y^2+3x)+25xy$ GTLN, GTNN tim gtln gtnn cho x,y khong am thay doithoa man x+y=1.tim GTLN,GTNN cua bieu thuc $$S=(4x^2+3y)(4y^2+3x)+25xy$$ GTLN, GTNN tim gtln gtnn Cho $x, y$ khong am thay doi thoa man $x+y=1$. Tim GTLN, GTNN cua bieu thuc $S=(4x^2+3y)(4y^2+3x)+25xy$ GTLN, GTNN

	2	sai đề		Sửa 12-04-16 09:42 PM ๖ۣۜDevilღ 1
tim gtln gtnn cho x,y khong am thay doithoa man x+y=1.tim GTLN,GTNN cua bieu thuc $$S=(4x^2+3y)(4y^2+3x)+25xy$$ GTLN, GTNN tim gtln gtnn cho x,y khong am thay doithoa man x+y=1.tim GTLN,GTNN cua bieu thuc $$S=(4x^2+3y)(4y^2+x)+25xy$$ GTLN, GTNN tim gtln gtnn cho x,y khong am thay doithoa man x+y=1.tim GTLN,GTNN cua bieu thuc $$S=(4x^2+3y)(4y^2+3x)+25xy$$ GTLN, GTNN

	1	tạo mới
tim gtln gtnn cho x,y khong am thay doithoa man x+y=1.tim GTLN,GTNN cua bieu thuc $$S=(4x^2+3y)(4y^2+x)+25xy$$

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