Tim GTLN
Cho:
x3+y3+3(x2+y2)+4(x+y)+4=0 va
$xy>0
$Tim GTLN cua:
$M=\frac{1}{x}+\frac{1}{y}$
GTLN, GTNN
Tim GTLN
Cho:
x3+y3+3(x2+y2)+4(x+y)+4=0 va xy>0Tim GTLN cua: M=
$\
tfrac{1}{x}+\
tfrac{1}{y}$
GTLN, GTNN
Tim GTLN
Cho:
x3+y3+3(x2+y2)+4(x+y)+4=0 va
$xy>0
$Tim GTLN cua:
$M=\frac{1}{x}+\frac{1}{y}$
GTLN, GTNN