Quay lại câu hỏi

	2	thêm 5 ký tự trong đề bài
giup minh bai nay voi ..ban oi $(4^{x^{2}}-16x+7)\times \log_{3}(x-3)$ $log^{2}_{9}x> \log_{3}x\times \log_{3}(\sqrt{2x+1}-1)$ Bất phương trình lôgarit giup minh bai nay voi ..ban oi $(4^{x^{2}}-16x+7)\times \log_{3}(x-3)$ $log^{2}_{9}x> \log_{3}x\times \log_{3}(\sqrt{2x+1}-1)$ Bất phương trình lôgarit giup minh bai nay voi ..ban oi $(4^{x^{2}}-16x+7)\times \log_{3}(x-3)$ $log^{2}_{9}x> \log_{3}x\times \log_{3}(\sqrt{2x+1}-1)$ Bất phương trình lôgarit

	1	tạo mới
giup minh bai nay voi ..ban oi $(4^{x^{2}}-16x+7)\times \log_{3}(x-3)$ $log^{2}_{9}x> \log_{3}x\times \log_{3}(\sqrt{2x+1}-1)$

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