giải pt 
$2\sqrt{x+2}=x^3-4$
$$<=>\sqrt{x+2}(2-\sqrt{x+2})=x^3-x-6$$
$$<=>\sqrt{x+2}(\frac{2-x}{\sqrt{x+2}+2})=(x-2)(x^2+2x+3)$$
$x=2=>>$
x#2 thì $\frac{-\sqrt{x+2}}{\sqrt{x+2}+2}=x^2+2x+3$
VP>0
VT<0
=> loại.
=> x=2 là nghiệm duy nhất./

<=>x+2(2x+2)=x3x6
<=>x+2(2xx+2+2)=(x2)(x2+2x+3)
x=2=>>
x#2 thì x+2x+2+2=x2+2x+3
VP>0
VT<0
=> loại.
x=2

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