Chứng minh các đẳng thức sau: 
a) $ \frac{sin^2a-cos^2a}{1+2sinacosa} = \frac{tana-1}{tana+1}$
b) $ \frac{sin^2a - tan^2a}{cos^2a - cot^2a} = tan^6a$
c) $ \frac{sin4a}{1+cos4a} . \frac{cos2a}{1+cos2a} = tana$
d) $ sin^4a + cos^4a = 1-2sin^2a.cos^2a = \frac{3}{4} + \frac{1}{4}cos4a $
e) $ \frac{cos^2a - sin^2a}{cot^2a - tan^2a} = sin^2a.cos^2a$
d) $sin^4a+cos^4a=sin^4a+2.sin^2a.cos^2a+cos^4a-2sin^2a.cos^2a$
$=(sin^2a+cos^2a)^2-2.sin^2a.cos^2a=1-2sin^2a.cos^2a$
CM: $1-2sin^2a.cos^2a=\frac{3}{4}+\frac{1}{4}cos4a$
$VT=1-2.(\frac{1}{2}.sin2a)^2=1-\frac{1}{2}.sin^22a$
$VP=\frac{3}{4}+\frac{1}{4}(1-2sin^22a)=1-\frac{1}{2}sin^22a$
=> $VT=VP$
c) $VT=\frac{2sin2a.cos2a}{1+2cos^22a-1}.\frac{cos2a}{1+2cos^2a-1}$
$=\frac{sin2a}{2cos^2a}=\frac{2sina.cosa}{2cos^2a}=tana=VP$
b) $VT=\frac{sin^2a-\frac{sin^2a}{cos^2a}}{cos^2a-\frac{cos^2a}{sin^2a}}$
$=\frac{sin^4a(cos^2a-1)}{cos^4a(sin^2a-1)}=\frac{sin^4a.(-sin^2a)}{cos^4a.(-cos^2a)}=tan^6a$
a) $VT=\frac{(sina-cosa)(sina+cosa)}{(sina+cosa)^2}=\frac{sina-cosa}{sina+cosa}=\frac{\frac{sina}{cosa}-1}{\frac{sina}{cosa}+1}=\frac{tana+1}{tana-1}=VP$


e) $VT=\frac{cos^2a-sin^2a}{cot^2a-tan^2a}=\frac{cos2a}{\frac{cos^2a}{sin^2a}-\frac{sin^2a}{cos^2a}}$
$=\frac{sin^2a.cos^2a.cos2a}{cos^4a-sin^4a}=\frac{sin^2a.cos^2a.cos2a}{(cos^2a+sin^2a)(cos^2a-sin^2a)}$
$=\frac{sin^2a.cos^2a.cos2a}{cos2a}=sin^2a.cos^2a=VP$

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