cHO tAM giác ABC vuông tại A đường cao AH, biết diện tích tam giác ABH, ACH lần lượt là 24 và 13,5 cm^2. tính AH ?
ta có: S ABH = 24 => 1/2.AH.BH= 24 => BH= 48/AH       (1)
         S ACH = 13,5 => 1/2.AH.CH= 27 => CH= 27/AH    (2)
   TỪ CÔNG THỨC AH^2= CH.BH  (3)
LẤY (1) VÀ (2) THAY VÀO (3) TA ĐƯỢC:
  AH^2 = 48/AH+27/AH
AH^4=1296
=> AH=+6 HOẶC AH=-6 DO AH DƯƠNG LOẠI AH=-6
=> VẬY AH=6

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