Cho hàm số   $y=\frac{x^3}{3}+\frac{x^2}{2}-2x-1=f(x)$  (C)
Chứng minh rằng pt  $f(x)$  có 3 nghiệm phân biệt
dat   y=f(x),thi  f(x) la   ham  phan   thuc  huu ti nen f(x) lien tuc tren R
$f(-4)=-19/3;f(-1)=7/6=>f(-4)f(-1)<0
 => pt  co   it  nhat  1 nghiem  x\in (-4;-1)   (3*)$
$f(-1)=7/6;f(0)=-1=>f(-1)f(0)<0$
pt $f(x) co  it   nhat  1  nghiem  x\in (-1;0)    (2*)$

$voi f(0)= -1 ,f(2)=5 =>f(0)f(2)<0$
pt f(x)  co it nhat 1 nghiem x$\in (0;2)    (*)$
tu *,2*,3*=> pt f(x) co 3 nghiem pb

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